Question

Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, −1).

Answer 1

help

Answer 2

@goformit100 help plz

Answer 3

@Aperogalics

Answer 4

ok
if we rearrange it it will become
comparing it with y=mx+c we get slope m=-3
so a line perpendicular to this line must have slope 'M' such that mM=-1
M=-1/-3=1/3
so y-y1=m(x-x1)
is the equation of line if m=slope and (x1,y1)=point given