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Is anyone really good at log???? Please let me know now!!:)
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you really should post an actual problem that you might need help on ....
hmmm, thats saying that 4^x = 32
8?
nevermind
4 = 2^2; 32 = 2^5 \[2^{2x}=2^{5}~;~ 2x=5\]is what my first idea is
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\[log_4(32)\] \[\frac{log_2(32)}{log_2(4)}\] \[\frac{5}{2}\] same same
\[log_4(32)\] \[log_4(4*4*2)\] \[log_4(4)+log_4(4)+log_4(2)\] \[1+1+\frac12=\frac52\]
i would log 25 each side
25^x-2=125 log_25(25^x-2)=log_25(125) (x-2) log_25(25)=log_25(125) x-2 =log_25(25*5) x-2 =log_25(25) + log_25(5) x-2 = 1 + 1/2 x = 2 + 1 + 1/2
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