Question

3/2 - 5/4 + 7/8 -9 /16 +11/32 - 13/64 ...
HOW do you write the series in summation notation !!

Answer 1

WELCOME :D BB

Answer 2

Does anyone know how to solve this?

Answer 3

NOPE SORRY

Answer 4

The numerator in each of these is odd starting with 3 and the denominator is powers of 2 starting with 2^1 and the sign is alternating so it would be

\[\sum_{n=0}^{\infty} \frac{(-1)^{n}(2n+3)}{2^{n+1}}\]

Answer 5

thnx!

Answer 6

Yup :)