Question

plse answer it

Answer 1

12- x^2 >= 0

solve for x

Answer 2

so is it right or wrong

Answer 3

agreed :)

Answer 4

thanks bro

Answer 5

\[12-x ^{2}\ge0,-x ^{2}\ge-12,x ^{2}\le12,\left| x \right|\le2\sqrt{3}\]
\[-2\sqrt{3}\le x \le2\sqrt{3}\]

Answer 6

\[domain is \left[ -2\sqrt{3},2\sqrt{3} \right]\]
\[range is \left[ 0,12 \right]\]