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Solve the following system of equations by the substitution method. 10x + 10y = 1 x = y - 3 What is the value of y? -29/20 31/20 -3/2
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Substitute x = y - 3 in the first equation and you should get : 10 ( y - 3 ) + 10y = 1 10y - 30 + 10 y = 1 Can you solve it now?
no
Okay, let's solve it further. 20y - 30 = 1 Now what do you do?
umm
Lol, still didn't get it? :)
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no
20y = -29 So, \[y = \frac{ -29 }{ 20 }\]
o ok thanks i get it now
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