Question

2x^2-12x+18

Answer 1

2x^2-12x+18 = 0 or is it just 2x^2-12x+18 ?

Answer 2

(2x-6)(x-3)?

Answer 3

Equation:

Solution for 2x^2-12x+18= equation:

Simplifying
2x2 + -12x + 18 = 0

Reorder the terms:
18 + -12x + 2x2 = 0

Solving
18 + -12x + 2x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2'.
2(9 + -6x + x2) = 0

Factor a trinomial.
2((3 + -1x)(3 + -1x)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(3 + -1x)' equal to zero and attempt to solve:

Simplifying
3 + -1x = 0

Solving
3 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1x = 0 + -3
-1x = 0 + -3

Combine like terms: 0 + -3 = -3
-1x = -3

Divide each side by '-1'.
x = 3

Simplifying
x = 3
Subproblem 2
Set the factor '(3 + -1x)' equal to zero and attempt to solve:

Simplifying
3 + -1x = 0

Solving
3 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1x = 0 + -3
-1x = 0 + -3

Combine like terms: 0 + -3 = -3
-1x = -3

Divide each side by '-1'.
x = 3

Simplifying
x = 3
Solution
x = {3, 3}

Answer 4

\[2x ^{2} - 6x - 6x + 18 =0\]
\[2x( x - 3 ) - 6 ( x - 3 )\]
\[(2x - 6 ) (x - 3)\]
If \[(2x - 6 ) (x - 3) = 0\] then,
x = {3, 3 }