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__ 3 ÷ √3 =
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what about|dw:1368130090360:dw|
@Luis_Rivera
Thanks how about (x*y)^-3= @Luis_Rivera ?
\[(xy){-3}= \frac{ 1 }{ (xy)^3} \\ =\frac{ 1 }{ \sqrt[3]{xy }}* \frac{ \sqrt[3]{xy } }{ \sqrt[3]{xy }}\\ = \frac{ \sqrt[3]{xy} }{ \sqrt[3]{xy}* \sqrt[3]{xy} }\\ =\frac{ \sqrt[3]{xy} }{ xy }\]
\[\sqrt[n]{ x^{ 3n}}= \ \ \sqrt{ x ^{3^{n}}}\ \ = x^3\]
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