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OpenStudy (anonymous):
what are the real or imaginary solutions of the polynomial equation x^3-8=0 please show all work. Thankyou.
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OpenStudy (anonymous):
x^3-8=0 x^3 = 8 x = cube root(8) x = 2 there are some imaginary solutions but i don't know how to get them. http://www.wolframalpha.com/input/?t=crmtb01&f=ob&i=x%5E3%20%3D%208
OpenStudy (anonymous):
I think you have to use the difference of cubes formula.
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