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Show that among all quadrilaterals of a given perimeter the square has the largest area.
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@nathan917
Please help me
@jim_thompson5910 @him1618
P = 2l + 2w A = lw => A = l(P - 2l)/2 = lP/2 - l² => dA/dl = P/2 - 2l = 0.....when area is maximum i.e. P = 4l so, 4l = 2l + 2w => 2l = 2w i.e. l = w.......a square I'm not sure.
Thank you Sir
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