Question

y=2x^2 -3
y=3x-1
solve the system of equations

Answer 1

did you try setting them equal to each other ?
if both = y, then you can say
2x^2 -3 = 3x -1

put it into standard form
\[ 2x^2 -3x -2 =0 \]
now you have to factor this quadratic.

Answer 2

that's all I had to do? I made too much work for myself

Answer 3

after you find x, you find y. use y=3x-1 (the other equation also works but it is more work)