Question

2x^2-5x-4=0
Using the quadratic formula

Answer 1

\[\Large x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\]


\[\Large x = \frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-4)}}{2(2)}\]


\[\Large x = \frac{5\pm\sqrt{25-(-32)}}{4}\]


I'll let you finish