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OpenStudy (anonymous):
Find the indefinite integral (3x-7)^-6dx
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hartnn (hartnn):
you can substitute u = 3x-7 then, du=... ?
OpenStudy (anonymous):
right, it would be ∫(3x-7) ^ 6 dx , substitute u = 3x -7 , du = 3dx , du/3 = dx . 1/3 *∫u^-6 , 1/3* -u/5 ^ -5 + C .
OpenStudy (anonymous):
sorry , 1/3 * (u)^-5/-5 + c , then replace u.
OpenStudy (anonymous):
Thank you! Trying to wrap my head around it!
OpenStudy (anonymous):
medal -.- ..
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