x^2 + y^2 + z^2 - 2x + 4z - 3 = 0 ,is given as an equation of a circle.how can it be if circle are 2 dimensional having x and y coordinates only?
the question was : find equation of sphere which passes through circle x^2 + y^2 + z^2 - 2x + 4z - 3 = 0,2x+y+z=4 and touch the plane 3x+4y-14=0.(dont need solution of question but the concept behind circle having three coordinates)

Question

x^2 + y^2 + z^2 - 2x + 4z - 3 = 0 ,is given as an equation of a circle.how can it be if circle are 2 dimensional having x and y coordinates only?
the question was : find equation of sphere which passes through circle  x^2 + y^2 + z^2 - 2x + 4z - 3 = 0,2x+y+z=4 and touch the plane 3x+4y-14=0.(dont need solution of question but the concept behind circle having three coordinates)

shubhamsrg · Answer

yes its not a circle :|

anonymous · Answer

you don't say ! but in the answer in the book its mentioned as a circle! and not in one question.

.sam. · Answer

attachment

anonymous · Answer

I still dont get it how its a circle with z axis...what r u saying?