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in triangle PQR, sin P =.4, sin R=.5 and r=14. find the length of p
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Use the sine Law : \[\Large \color{Red}{\frac{a}{SinA}=\frac{b}{SinB}}\]
p/.4=14/.5
Exactly :) now solve for p
14(.4)/.5 =p
p=11.2
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Right :)
yay will you help me with more
Sure :3
okay in triangle PQR, sin P=.6, sin R=.6, and r=16 find the length of p
Apply the same steps
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.6/p=.6/16 -> 16(.6)/.6=p ->p=16
Good job !
okay i think i can do the rest now but if i have any other questions ill askit and link you to it
Feel free to msg me :)
Good Luck !
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gah new question okay in triangle ABC m<b=16 m<c=62, a=22 find the length of b
nvr mind
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