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Mathematics 13 Online
OpenStudy (anonymous):

Connections

OpenStudy (anonymous):

Find the value of x If needed round to nearest tenth

OpenStudy (loser66):

|dw:1368194685521:dw|

OpenStudy (loser66):

use pythagorean to find x = sqrt( 9^2 + 6^2)

OpenStudy (anonymous):

can you work out and show me steps

OpenStudy (loser66):

do you agree with me that x is radius of the circle?

OpenStudy (anonymous):

Only a little

OpenStudy (loser66):

why?|dw:1368195405602:dw|

OpenStudy (loser66):

is it not right?

OpenStudy (anonymous):

okay .

OpenStudy (loser66):

and the radius perpendicular to the line at the middle of that line, is it ok?

OpenStudy (anonymous):

sure

OpenStudy (loser66):

so, look at my pic, HB =6 , OH = 9 --> OB = sqrt(9^2 +6^2) by Pythagorean theorem. got it?

OpenStudy (anonymous):

so like 7 ish but that not correct

OpenStudy (loser66):

10.81 my TI said that

OpenStudy (loser66):

|dw:1368196048899:dw|

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