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when x^-1 is divided by x-1 the quotient is
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Factor x^2 - 1 HINT: Difference of two squares \[\large (p^2 - q^2) = (p+q)(p-q)\]
my problem is x to the negative 1st power not x^2
Whoops... I'm sorry, I must have been seeing things :) If that's the case, then. \[\huge \frac{x^{-1}}{x-1}= x^{-1}\cdot \frac{1}{x-1}\] and the fact that \[\huge x^{-1} = \frac1x\]
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