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Mathematics 7 Online
OpenStudy (anonymous):

Find the volume of the given prism. Round to the nearest tenth.

OpenStudy (anonymous):

OpenStudy (anonymous):

need help with these questions???

OpenStudy (anonymous):

265.1 cm3 274.6 cm3 269.3 cm3

OpenStudy (anonymous):

Q 2 is 924

OpenStudy (anonymous):

thank u

OpenStudy (anonymous):

What about 3?

OpenStudy (anonymous):

Q1 is 269.3

OpenStudy (anonymous):

Find the volume of the given prism. Round to the nearest tenth. a) 2,028.0 yd3 b) 1,756.3 yd3 c) 3,512.6 yd3

OpenStudy (anonymous):

thanks for the 1 :)

OpenStudy (anonymous):

i need help with them all except the last 3

OpenStudy (anonymous):

q10 is 4189

OpenStudy (anonymous):

Thank u

OpenStudy (anonymous):

Q3 is 1,756.3 yd3 well i got 1762.8 so i wreckon its that

OpenStudy (anonymous):

oh ok ty for that 1 :)

OpenStudy (anonymous):

ok then for q7 i got 1092.72 so its close to 1,093.3 m3 so i dunno

OpenStudy (anonymous):

Yea that is the same answer i got for that 1 also that one was weird lol well ty for that one

OpenStudy (anonymous):

ty so much for helping me with these

OpenStudy (anonymous):

am no probs there is ome i haven't a clue on like but i will help with the ones i can :)

OpenStudy (anonymous):

Q5 is 768

OpenStudy (anonymous):

ty :) and also i appreciate that also...

OpenStudy (anonymous):

so for q6 i got root69 for h but then when i put all of it in the formula i got 276.8 so i dunno bout that one

OpenStudy (anonymous):

i haven't a clue how to the last 5 sorry

OpenStudy (anonymous):

V=1/3 (area of base) (height) to find h 13^2=10^2+h^2

OpenStudy (anonymous):

yea i got root 69 for h then the base is 10 by 10 so thats 100 then you put it all into the formula and i got 376.8 which isn't one of the options so not to sure bout that one

OpenStudy (anonymous):

oh i see what u mean now :-/

OpenStudy (anonymous):

yeah i mean if you did a 1/3 by 100 then u would get 33.3 which is an option but its not right so i dunno ..

OpenStudy (anonymous):

I guess ill go with that 1 because that is the only answer we can come up with ty with that one :)

OpenStudy (anonymous):

ok and for q4 i got a completely different answer..than whats there

OpenStudy (anonymous):

for 4 v=Pi^2h

OpenStudy (anonymous):

that was the hint i got which i think u know that lol

OpenStudy (anonymous):

yeah when i put all the ifo in so its like \[\Pi \times 3.4^{2} \times 11 = 399.48\]

OpenStudy (anonymous):

Hu that is weird i wonder y that happened

OpenStudy (anonymous):

i think for that question for what i got i think it is B which is 432.34 m^3

OpenStudy (anonymous):

i dunno either i'm going extremly wrong or you have a messed up paper :L

OpenStudy (anonymous):

Lol

OpenStudy (anonymous):

Dumb teachers lol

OpenStudy (anonymous):

What about 9?

OpenStudy (anonymous):

haha know how ye feel :L

OpenStudy (anonymous):

am hold on a sec i will try it now

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

I think it is B i am like 55% sure so i want ur input on this one if u can...

OpenStudy (anonymous):

i got 81 fot that one do you want me to show u how i did it ?

OpenStudy (anonymous):

if u dont mind ya

OpenStudy (anonymous):

yeah no probs

OpenStudy (anonymous):

cool

OpenStudy (anonymous):

so to get the circumfrence of a circle it 2 by pi by r so you let that formula = 16 then pi is also equal to 3.14 so multiply 3.14 by 2 =6.28

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

\[6.28r=16 \]

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

then r = 16 divided by 6.28 which is 2.54

OpenStudy (anonymous):

now you have r just fill out the formula

OpenStudy (anonymous):

oh i see now

OpenStudy (anonymous):

\[4 \times \Pi \times 2.54^{2} = 81.07\]

OpenStudy (anonymous):

ok cool

OpenStudy (anonymous):

how about 12?

OpenStudy (anonymous):

okay cool soz i couldn't helo with the last few ive no clue

OpenStudy (anonymous):

i dunno how to do the rest sorry

OpenStudy (anonymous):

ok well well ty for ur help with all the one's u helped me with ty so much if i could give ya a hug right now i would ty SOOO much :)

OpenStudy (anonymous):

lol ;)

OpenStudy (anonymous):

haha awww honestly its no problem just out of intrest what year maths is that ?

OpenStudy (anonymous):

11th grade

OpenStudy (anonymous):

Geometry

OpenStudy (anonymous):

okay cool same level as me then :L

OpenStudy (anonymous):

What school r u in??

OpenStudy (anonymous):

i am in Commonwealth connections academy

OpenStudy (anonymous):

am in a school in ireland middle of no where :L

OpenStudy (anonymous):

A cool lmao!!!!!

OpenStudy (anonymous):

well ty for ur help tweet me some time @jakeconrad33

OpenStudy (anonymous):

okay i'm not on twitter tho soz

OpenStudy (anonymous):

oh well that would be hard then to tweet me lol do u have kik?

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