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Algebra
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find the value of the expression 9P3
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use this formula : nPr = n!/(n-r)! with n! = n(n-1)(n-2)(n-3)... 3.2.1
in this case, known the value of n=9 and r=3
i have to show my work how do i do tht
9P3 = 9!/(9-3)! = 9!/6! = ... simplify
is it 504
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yup that's right
thank you
you're welcome
okay simplify this expression 10C4
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