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what are the solutions to z^2 -6z-27=0
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-9, -3
What have you done so far with the question @minimoo
factored it out to be (z-9)(z+3)
Yep that's good. Now you have this: \[(z-9)(z+3)=0\] What values of z make the equation zero?
it would be z-9=0 and z+3=0 and the answers would be 9 and -3
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Well Done! That's correct.
:) im getting the hang of it!
Yep, you don't need to fret about this too much because if you try attempting it, you would be likely to get it right! ;)
thanks again :)
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