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16+8+4+2+1+... (find the infinite sum of the geometric series)
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the first term is a = 16 the common ratio is r = ???
I don't know
what are you multiplying 16 by to get to 8?
duh 1/2 :)
so a = 16 r = 1/2
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plug this into S = a/(1-r) Note: this formula only works if |r| < 1, which is true in this case (since |1/2| < 1 is true)
32 got it .. Thank you so much. FInal on Monday and trying to figure all this out
32 is correct, yw
can I ask another question while I have you attention
good luck and i'm sure you'll do well
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sure whats up
|dw:1368235528107:dw|] sorry about the drawing :)
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