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Mathematics 19 Online
OpenStudy (anonymous):

limit of x as x approaches 0 of... (sinx)/(1+cosx)= ?

hartnn (hartnn):

approaches 0 ? just plug in x=0

hartnn (hartnn):

or is it 1-cos x ?

OpenStudy (anonymous):

oh.. Yeah I did that and got 0. Thought it'd be wrong

hartnn (hartnn):

0 is correct :)

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