Please can Any One help?
Assume that each person in a population has chance 2/1000 of carrying a particular disease, independently of all other people. Among 1000 people in this population, the number of people that carry the disease [pick all that are correct]
my approach:

Plot that binomial distribution! Does it look like a normal distribution to you? Hint: What's the probability that there's one infected person? What's the probability that there are two? Three? More than 10? From those values, answer whether the distribution looks skewed. If it does - can it be approximately normal? Can a normal distribution be skewed.

P=2/1000=0.002
n=1000
Mean=μ=n*p=0.002*(1000)=2
σ=SQRT(n∗p∗(1−p))=SQRT(1000*0.002*(0.998))= 1.413; z=(x−μ)/σ
a-) Has a distribution that is approximately normal
b-) Has a binomial distribution
c-) Has a hyper-geometric distribution
d-) Has a distribution that is right-skewed
e-) Has a distribution that is left-skewed

Question

Please can Any One help? 
Assume that each person in a population has chance 2/1000 of carrying a particular disease, independently of all other people. Among 1000 people in this population, the number of people that carry the disease [pick all that are correct]
my approach:

Plot that binomial distribution! Does it look like a normal distribution to you? Hint: What's the probability that there's one infected person? What's the probability that there are two? Three? More than 10? From those values, answer whether the distribution looks skewed. If it does - can it be approximately normal? Can a normal distribution be skewed.

P=2/1000=0.002
n=1000
Mean=μ=n*p=0.002*(1000)=2
σ=SQRT(n∗p∗(1−p))=SQRT(1000*0.002*(0.998))= 1.413; z=(x−μ)/σ
a-) Has a distribution that is approximately normal
b-) Has a binomial distribution
c-) Has a hyper-geometric distribution
d-) Has a distribution that is right-skewed
e-) Has a distribution that is left-skewed