Question

Two point charges q1 and q2 are placed .30m apart on the x axis. q1 charge is -3*10^-9 C. A point P is at -.20m with electric field 0 ( q1 at -.10m, q2 at .20m) . What is the magnitude of the electric force on q2?

Answer 1

For total E(electric field) to be =0 must E1=E2
K\[K*\frac{ q1 }{ d _{1}^2 }=K*\frac{ q2 }{ d _{2^2} }\]