Question

Find the equation of a line that is perpendicular to the line y = 1/3x+8 and contains (-9,0)

Answer 1

the slope of y = 1/3x+8 is m = ______

Answer 2

1/3 ?

Answer 3

flip the fraction to get ____

Answer 4

3

Answer 5

now change the sign to get ____

Answer 6

-3

Answer 7

so that's the slop of ANY line perpendicular to y = 1/3x+8

Answer 8

y = mx+b

y = -3x + b ... plug in the perpendicular slope

0 = -3(-9) + b ... plug in the given point (-9,0)

now solve for b

Answer 9

slope*

Answer 10

b = -27?

Answer 11

m = -3
b = -27


y = mx+b

y = -3x + b

y = -3x - 27

That's the equation of the perpendicular line to y = 1/3x+8

Answer 12

Thank you so much for walking me through it!!

Answer 13

and that goes through (-9,0)

Answer 14

you're welcome