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2log(7) -2r=0
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same base. Just throw the logs away.
Notice, if the logarithm on both sides has the same base, then the terms of which the logarithm is being taken of for both sides are equal.\[\bf \log(10-4x)=\log(10-3x) \implies 10-4x=10-3x\]Now rearrange and solve for x.
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