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integrate (x^3+x^4tanx) dx from x=-pi/4 to pi/4
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\[\int\limits_{-\pi/4}^{\pi/4} (x^3+x^4tanx) dx\]
check whether x^3+x^4 tan x is odd function or not. if its an odd function, then the integral =0
the function is odd if f(x) = -f(-x) and a property of indefinite integral is \(\int \limits_{-a}^af(x)dx=0\) if f(x) is odd function, \(\int \limits_{-a}^af(x)dx=2\int \limits_{0}^af(x)dx\) if f(x) is even function.
what if its neither lol
if its neither, you have to integrate the function as it is....no simplification...
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