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Precalculus
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solve (x+7)^2=33
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\( (x+7)^2=33\) take square root both sides. this gives u \(\sqrt{(x+7)^2}=\pm\sqrt{33}\) \(x+7=\pm\sqrt{33}\) does that help? @tjdenerson
yes
do i subtract
7
yup. there will be two values for x. \(x+7=\sqrt{33}\) or \(x+7=-\sqrt{33}\)
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ok
so its simplified completely
the answer u get aftr subtracting 7 is a simplified one.
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