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Precalculus 9 Online
OpenStudy (anonymous):

solve (x+7)^2=33

OpenStudy (ajprincess):

\( (x+7)^2=33\) take square root both sides. this gives u \(\sqrt{(x+7)^2}=\pm\sqrt{33}\) \(x+7=\pm\sqrt{33}\) does that help? @tjdenerson

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

do i subtract

OpenStudy (anonymous):

7

OpenStudy (ajprincess):

yup. there will be two values for x. \(x+7=\sqrt{33}\) or \(x+7=-\sqrt{33}\)

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

so its simplified completely

OpenStudy (ajprincess):

the answer u get aftr subtracting 7 is a simplified one.

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