Question

x^2+3x-28=0

Answer 1

Are you trying to find roots?

Answer 2

no solve

Answer 3

x^2-4x+7x-28=0
(x-4)(x+7)=0

Answer 4

1. Subtract both sides by 28.
2. Factor the polynomial.
3. Set each binomial to zero and find x.

x²-3x-28=0
(x-7)(x+4)=0
x-7=0 or x+4=0
x={7,-4}

Answer 5

http://www.algebrahelp.com/calculators/equation/

Answer 6

@nathan917 wrong solution

Answer 7

@nathan917 your answers are not correct

Answer 8

oops.

Answer 9

(:

Answer 10

x-4=0,x+7=0