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wut do u need help on? post a pic or paste the question and maybe I can help :)
It's a trig question: sin(4 * theta) = cos(2 * theta)
ughhhh haven't learned that yet pal.. im sorry.. :(
That's alright, thanks for trying!
aww ok sorry again :)
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ima add u in case u need anything else
there added u
sin(4θ) = cos(2θ) 2sin(2θ)cos(2θ) = cos(2θ) 2sin(2θ)cos(2θ) - cos(2θ) = 0 factor out! cos(2θ) (2sin(2θ ) - 1) = 0 for the zeroes take each factor then setting be equal zero cos(2θ) = 0 or 2sin(2θ) - 1 = 0 solve for θ ...
Thanks guys, really helped!
you're welcome
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