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Mathematics
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Evaluate the indicated integral.
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let u = x^2 + 4 ----> du = 2x dx = \[1/2 \int\limits_{}^{} \frac{ du }{ u }\]
integrate for u and plug u = x^2 + 4 back in
\[Let I =\int\limits_{}^{}\frac{ x }{ x ^{2}+4 }dx=\frac{ 1 }{2 }\int\limits_{}^{}\frac{ 2xdx }{ x ^{2}+4 }\] \[I=\frac{ 1 }{ 2 }\ln \left( x ^{2}+4 \right)+c\]
okay i did it wrong before i got log(x) + c but okay
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