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Can someone please help me with this
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|dw:1368384221304:dw|
Area enclosed by ripple, A = \(\pi r^2\) -------- (1) rate of change of A, dA/dt = 2.pi.r. dr/dt = 2.pi.r.4 = 8.pi.r -----------------(2)
ok
its Given : after 10 seconds, dA/dt = k.pi
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k=8
so, at 10 seconds :- dA/dt = 8.pi.r = k.pi => k = 8.r
what is the r
good q, since r is changing at 4 ft/s, at 10th second r = 4*10 = 40 so k = 8.r = 8 * 40 = ?
320
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os then the 320 is my final answer correct?
yep !
ok thanks
np
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