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Mathematics 15 Online
OpenStudy (anonymous):

Can someone please help me with this

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

|dw:1368384221304:dw|

ganeshie8 (ganeshie8):

Area enclosed by ripple, A = \(\pi r^2\) -------- (1) rate of change of A, dA/dt = 2.pi.r. dr/dt = 2.pi.r.4 = 8.pi.r -----------------(2)

OpenStudy (anonymous):

ok

ganeshie8 (ganeshie8):

its Given : after 10 seconds, dA/dt = k.pi

OpenStudy (anonymous):

k=8

ganeshie8 (ganeshie8):

so, at 10 seconds :- dA/dt = 8.pi.r = k.pi => k = 8.r

OpenStudy (anonymous):

what is the r

ganeshie8 (ganeshie8):

good q, since r is changing at 4 ft/s, at 10th second r = 4*10 = 40 so k = 8.r = 8 * 40 = ?

OpenStudy (anonymous):

320

OpenStudy (anonymous):

os then the 320 is my final answer correct?

ganeshie8 (ganeshie8):

yep !

OpenStudy (anonymous):

ok thanks

ganeshie8 (ganeshie8):

np

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