Question

HELP! PLEASE completing the square
Solve 4x² =- 8x + 12

Answer 1

Could any of you help me?

Answer 2

@brookester6 could help me?

Answer 3

set it to 0

Answer 4

0=4x^2=-8x+12?

Answer 5

wait, thats if your factoring lol

square each side

Answer 6

I'm not sure how to do that

Answer 7

X = -3 x = 1

Answer 8

What are the steps that I would take to get that answer?

Answer 9

thats factoring..

Answer 10

\[4x ^{2}=-8x+12\]
\[4x ^{2}+8x-12=0\]
Divide by 4 on both sides
\[x ^{2}+2x-3=0\]
\[x ^{2}-x+3x-3=0\]
\[x(x-1)+3(x-1)=0\]
\[(x-1)(x+3)=0\]
So,
x=1 or x=-3

Answer 11

Solve for x over the real numbers:
4 x^2 = 12-8 x
Subtract 12-8 x from both sides:
4 x^2+8 x-12 = 0
The left hand side factors into a product with three terms:
4 (x-1) (x+3) = 0
Divide both sides by 4:
(x-1) (x+3) = 0
Split into two equations:
x-1 = 0 or x+3 = 0
Add 1 to both sides:
x = 1 or x+3 = 0
Subtract 3 from both sides:
Answer: |
| x = 1 or x = -3

Answer 12

Aweosme! Thank you all so much. I appreciate it. Very helpful.

Answer 13

@Brookebrookiee no problem.