Question

Homework 9
Lab 9

Answer 1

1. 126.5e-12
2. 25000
3. Duty Cycle 58 and check TRAN

Answer 2

@Nurali first two values work well but 3 point gives wrong lab figure.
can u pls review

Answer 3

square wave period T = 1/f = 1/30,000
duty cycle DC = .58
(VL/L) dt = di
with S1 closed IL increase to (3/2m) (1/30,000) (1- .58) = 21 mA
when S1 opens the field across inductor adjust to forward bias diode as 21 mA current passes through to load. because T << RLCL = 1 ms a ramp occurs until S1 closes and diode is reversed giving a .58T constant. This ramp-step action continues and because the inductor current never returns to zero it increase 21 mA every time S1 is closed until all the current goes though RL giving a final output where the current though the closed S1 is the same as though RL. The final output would depend on S1 closed resistance because it must drop 3 V at this point.

Answer 4

@sajid092 for part 2 R= 25500

Answer 5

@sajid092 for part 3 set duty cycle to 58 and run 10m trans analysis. Waveform will be like very high frequencies overlapping with each other

Answer 6

Part 3: Something Like this. :(
anf answers to homework 9 as well

Answer 7

Lab 9 Completed. Thank you Frnds

Answer 8

anytime.

Answer 9

THNX FRNDS