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OpenStudy (anonymous):
***ANSWER FOR A MEDAL AND FAN!!!*** Write the equation in standard form. 2x^2+2y^2+12x-8y+24=0
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OpenStudy (raden):
2x^2+2y^2+12x-8y+24=0 first, all divide by 2 x^2+y^2+6x-4y+12=0 then add by 1 to both sides, x^2+y^2+6x-4y+12+1=0+1 (x^2+6x+9)+(y^2-4y+4)=0+1 (x+3)^2 + (y-2)^2 = 1 it is an equation of circle with the centre (-3,2) and its radius r = 1
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