Ask your own question, for FREE!
MIT 6.002 Circuits and Electronics, Spring 2007 13 Online
OpenStudy (anonymous):

h.w.9 answers plzzzz

OpenStudy (anonymous):

paa g mily to mujhy b tag karna

OpenStudy (anonymous):

ok :)

OpenStudy (anonymous):

h9p1 1. 0.249 2. 35/2

OpenStudy (anonymous):

h9 p2 a) L*C b) L/R c) 1 d) sqrt(1/(L*C))/(2*pi) e) 1/(2*R*C) f) R*sqrt(C/L) g) 0.5*sqrt(L/C)

OpenStudy (anonymous):

h9 p3 b/(2*m) sqrt(k/m) sqrt(k/m)/(2*pi) 2*sqrt(k*m)

OpenStudy (anonymous):

@aaban chaa gye bawa G

OpenStudy (anonymous):

how about h9p1 rest of all parts and Lab Part 3 as well.

OpenStudy (anonymous):

h9 p1 0.249 35/2 35/2 0 ? 0 0 0

OpenStudy (anonymous):

At the time just before the impulse happens what is the voltage Vc(9.0-) , in Volts, across the capacitor?

OpenStudy (anonymous):

i know the formula but answer is remarked wrong vC(t) = -L*2*pi*f*sin(2*pi*f*t)

OpenStudy (anonymous):

-54.67

OpenStudy (anonymous):

@aaban, I wish I cud offer u a Coke chilled.

OpenStudy (anonymous):

thanz aaban

OpenStudy (anonymous):

can anyone tell me how to do the last problem of lab9 ?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!