Question

What is the solution to the equation 4^(-2x)=3?
x= -.631
x=-.396
x=.396
x=.631

Answer 1

\[\frac{ 1 }{ 4^{2x} }=3\]

\[\frac{ 1 }{ 3 }=4^{2x}\]

\[0.33=4^{2x}\]

Log both sides

\[\log(0.33)=\log(4^{2x})\]

\[-0.48=2xlog(4)\]

\[-0.48=2x(0.60)\]

\[-0.48=1.20x\]

\[x=-0.4\]

Answer 2

that's not one of the answers?