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Simplify. -14x^3/x^3-5x^4 from connections acadamy i sck at this
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\[\frac{ -14x^3}{x^3-5x^4} \] like that?
factor out a \(x^3\) from the denominator, then cancel it
i still dont get how to do it im rlly ad at math
\[\frac{ -14x^3}{x^3-5x^4}=\frac{-14x^3}{x^3(1-5x)}=\frac{-14}{1-5x}\]
-14\[-14/{1-5x}\]
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so the answer would be: -14/1-5x;where x is not equal to 1/5
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