Question

what is the standard form of the parabola with the vertex at the origin and the focus of (0,6)

Answer 1

i need a reply so i can finish my homework.

Answer 2

4ay=x^2, maybe; given that a = 6

Answer 3

you might have to consult your text or material for what "standard" form looks like in this context

Answer 4

standard form :
\[y = ax^{2} + bx +c\]
vertex (0,0)
c=0
b=0
\[a = \frac{1}{4p}\]
where p is distance from vertex to focus
p=6
a = 1/24

\[y = \frac{1}{24}x^{2}\]