1. An attractive force of 7.2 N occurs between two point charges that are 0.10 m apart. If one charge is -4.0 µC, what is the other charge? (µC = 1.0 × 10^-6 C)

-4.0 µC

-2.0 µC

+2.0 µC

+4.0 µC

Question

1. An attractive force of 7.2 N occurs between two point charges that are 0.10 m apart. If one charge is -4.0 µC, what is the other charge? (µC = 1.0 × 10^-6 C)

-4.0 µC

-2.0 µC

+2.0 µC

+4.0 µC

anonymous · Answer

$$F=k \frac{ Q_1Q_2 }{ d^2 }$$
F=Force between the two point charges
k=Coulomb's law constant (9.0*10^9)
Q(1)=amount of charge on one of the point charges
Q(2)=amount of charge on the other point charge
d=distance apart

anonymous · Answer

|dw:1368479128434:dw|