What's tha value of x?
sec∠C - cot∠A = 3x
a-
7−13−−√18

b-
13−−√3

c-
313−−√13

d-
6−13−−√7
i got a

Question

What's tha value of x?
sec∠C - cot∠A = 3x
a-
7−13−−√18

b-
13−−√3
		 
		 
c-
313−−√13

d-
6−13−−√7
i got a

anonymous · Answer

@ganeshie8

agent0smith · Answer

What are angles A and C...? Is there a diagram?

anonymous · Answer

http://assets.openstudy.com/updates/attachments/4f621256e4b079c5c6312df0-pineapple31-1331827292396-4.gif

anonymous · Answer

@agent0smith

anonymous · Answer

@ganeshie8

agent0smith · Answer

Do you know how to find secC from that pic? It's equal to 1/cosC (cosine is adjacent/hypotenuse)

cotA is 1/tanA, or you can just use adjacent/opposite. 

You will need to find side AB, using Pythagoras $$\Large 7^2 = 6^2 + AB^2$$