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Mathematics 12 Online
OpenStudy (anonymous):

Calculus min/max problem

OpenStudy (anonymous):

\[f(x) = \cos^2(x)-2\sin(x)\] \[x \epsilon [0,2\pi]\]

OpenStudy (anonymous):

just need a confirmation on what you got for your local max / min. I got for my local max at x = pi/2 Local min at x = 3/2 pi

OpenStudy (anonymous):

having contradictions with using the closed interval method and using the sign table. I am getting the exact opposit when I use either so not sure...

OpenStudy (anonymous):

@jhonyy9

OpenStudy (anonymous):

@julian25

OpenStudy (anonymous):

got for my local min at x = pi/2 Local max at x = 3/2 pi

OpenStudy (anonymous):

why u dont test ur answers making the graph

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