Question

a line has a slope of 0.5 and a y-intercept of (0,-2). what is the calue of y when x=4

Answer 1

this means -2-y/0-4
Do your algebra and find the value of y

Answer 2

let's write that as a formula in y-intercept form, \(y=mx+b\) where \(m\) is the slope and \(b\) is the y-intercept:\[y=(0.5)x+(-2)\]simplified to be written as:\[y={1\over2}x-2\]now let's plug in \(x=4\):\[y={1\over2}(4)-2\]\[y={4\over2}-2\]\[y=2-2\]\[y=0\]at \(x=4\) , \(y=0\)

Answer 3

i get it now thank you :)