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4i(1-2i)(3-i)
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U time 4i for (1-2i) first, then u take those answer times for (3-I)
It is exactly as AnnaT said. 4i(1-2i)(3-i) (4i-8i^2)(3-i) 12i-4i^2-24i^2+8i^3 12i-28i^2+8i^3
thanks yall
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