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What is the solution of the system? Use elimination. 3x – 4y = –24 x + y = –1 A. (–4, 3) B. (0, 6) C. (3, 4) D. (4, 3)
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@BacardiDavis D?!?
you have x + y = –1 (EQN 1) and you want to use elimination... so 3 (EQN 1) = 3x + 3y = -3 so 3x = -3 -3y
so A? lol
call 3x = -3 -3y (eqn 1a) so 3x = 4y - 24 and 3x = -3 -3y so 4y - 24 = -3 -3y
can you get it from here?
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yeah thanks :p
:p
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