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Mathematics 18 Online
OpenStudy (anonymous):

∫xsqrt(2x+1)dx

OpenStudy (amistre64):

by parts might be simple enough

OpenStudy (anonymous):

Nooooo were not in there yet

OpenStudy (amistre64):

i dont readily see a nice u-sub ......

OpenStudy (callisto):

Let u= 2x+1?

OpenStudy (anonymous):

du = 2dx? what happens to the x outside of the sqrt function

OpenStudy (raden):

by u-subs let u = 2x+1 ----> x = (u-1)/2

OpenStudy (callisto):

∫xsqrt(2x+1)dx u = 2x+1 du = 2dx \[∫x\sqrt{2x+1}dx\]\[=\frac{1}{2}\int(\frac{u-1}{2})\sqrt{u}du\]\[=\frac{1}{4}\int (u^\frac{3}{2}-\sqrt{u})du\]\[=...\]

OpenStudy (amistre64):

....bleh!! like i said, simply hideous ;)

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