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∫xsqrt(2x+1)dx
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by parts might be simple enough
Nooooo were not in there yet
i dont readily see a nice u-sub ......
Let u= 2x+1?
du = 2dx? what happens to the x outside of the sqrt function
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by u-subs let u = 2x+1 ----> x = (u-1)/2
∫xsqrt(2x+1)dx u = 2x+1 du = 2dx \[∫x\sqrt{2x+1}dx\]\[=\frac{1}{2}\int(\frac{u-1}{2})\sqrt{u}du\]\[=\frac{1}{4}\int (u^\frac{3}{2}-\sqrt{u})du\]\[=...\]
....bleh!! like i said, simply hideous ;)
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