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Physics 6 Online
OpenStudy (anonymous):

Hi, I found on WEB the circuit: http://hyperphysics.phy-astr.gsu.edu/hbase/electronic/square.html#c1 The formulas are exactly was I looking for, but the 'real' circuit is a little different, since it has a third resistor connected from Vcc to the inverting input (it makes a voltage divider). All 3 resistors have the same value. Now I have 2 possible values for lambda, depending on the comparator output state (high or low). The voltage divider creates 1/3 or 2/3 Vcc reference. How can I adjust the formulas to get the output frequency? Thanks

OpenStudy (anonymous):

Hi, I repost (possibly) this question since I think to have closed it in error. Apologize for this but this forum is new for me and I'm not sure of what to do. Thanks

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