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what is the curvature of y=x"3
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k=1/r sounds familiar
all thats needed now is to decipher that notation ....
give me more detail about it plz???
the curvature of a function at a point relates to the radius of the osculating circle (tangent circle?) at a given point.
without knowing anything else about the problem posted, its hard to be any more descriptive
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sir kindly solve it
i would if i could figure out what y=x"3 meant.
sir its mean y=x(power 3)
Find the curvature of y = x 3???
ahh, x^3
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\[k=\frac{|y''|}{(1+(y')^2~)^{3/2}}\]
y = x^3 y' = 3x^2 y'' = 6x \[k=\frac{|6x|}{(1+9x^4)^{3/2}}\]
thanx thanx sir (y)
youre welcome
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