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What is the standard form of the equation of teh circle in the graph?
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A. (x + 3)2 + (y - 1)2 = 1 B.(x - 3)2 + (y + 1)2 = 2 C.(x - 3)2 + (y + 1)2 = 1 D.(x + 3)2 + (y - 1)2 = 2
according that figure, known the centre of circle is (-3,1) and its radius r = 1 so, it is A
C.(x - 3)2 + (y + 1)2 = 1 taht what I Get?
oow okay thancks
you're welcome :)
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Which point lies outside the circle with equation (x - 2)2 + (y + 3)2 = 4? A.(1, -4) B.(0, -3) C.(2, 0) D.(2, -4) i get D is correct
Sorry Is The Last Question? I Just want if i"m correct or not?
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