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Mathematics 6 Online
OpenStudy (anonymous):

Consider the following recurrence relation. see screenshot..

OpenStudy (anonymous):

OpenStudy (anonymous):

@amistre64

OpenStudy (amistre64):

P(0) = 0 P(1) = P^2 (0) - 1 P(2) = P^2 (1) - 2 etc ....

OpenStudy (anonymous):

So P(1)=-1 P(2)=0 P(3)=0 P(4)=0???

OpenStudy (amistre64):

0 0^2 - 1 = -1 (-1)^2 - 2 = -1 (-1)^2 - 3 = -2 (-2)^2 - 4 = -1 (-1)^2 - 5 = -4 etc

OpenStudy (amistre64):

... -2^2 = 4, -4 = 0 i forgot how to add

OpenStudy (anonymous):

great explanation.. thank u much

OpenStudy (amistre64):

hope you can read thru the errors ;)

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