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Mathematics
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simplify
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what
\[\frac{ x ^{2}-3x-10 }{ x+2 }\]
x^2-3x-10 = (x-5)(x+2) so (x^2-3x-10)/(x+2) = (x-5)(x+2)/(x+2) = x-5
where \[x \neq-2\] or where \[x \neq5\]
where x not equal to -2, you can have x = 5
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(x+2)(x-5)/(x+2) after eliminating or canceling out (x+2) youget x-5
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